1. |
Find the alkyl ion series in the spectra below. (Check the hint!)
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Click on image to enlarge
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a)
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29, 43
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b)
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43, 57
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c)
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none
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2. |
Find the alkyl LOSS ion series in the same spectra shown below. (Check the hint!)
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Click on image to enlarge
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a)
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29, 43
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b)
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43, 57
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c)
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none
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3. |
For this same spectrum, choose the compound that the spectrum represents.
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Click on image to enlarge
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a)
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4-heptanone
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b)
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3-methyl-2-butanone
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c)
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3-pentanone
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d)
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2-butanone
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e)
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2-pentanone
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4. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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2-heptanone
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b)
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4-heptanone
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c)
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3-pentanone
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d)
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4-methyl-2-heptanone
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e)
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2,4-dimethyl-3-pentanone
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5. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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cyclobutanone
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b)
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2-butanone
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c)
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2-propanone
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d)
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3-pentanone
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e)
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1-hydroxy-2-propanone
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6. |
How many oxygens are in the molecular ion peak in this spectrum? (Check the hint!)
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Click on image to enlarge
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a)
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0
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b)
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1
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c)
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2
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d)
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3
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7. |
For this same spectrum, choose the compound that the spectrum represents.
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Click on image to enlarge
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a)
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4-methyl-cyclohexanone
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b)
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2,4-pentanedione
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c)
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2-hexanone
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d)
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3,3-dimethyl-2-butanone
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e)
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cyclohexanone
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8. |
In this spectrum, the molecular ion is 98 and there is one oxygen atom. Calculate the number of rings + double bonds in this compound. (Check the hint!)
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Click on image to enlarge
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a)
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0
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b)
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1
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c)
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2
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d)
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3
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9. |
For this same spectrum, choose the compound that the spectrum represents.
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Click on image to enlarge
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a)
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3-methyl-2-butanone
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b)
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2-hexanone
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c)
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4-methyl-3-penten-2-one
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d)
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3-methyl-2-pentanone
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e)
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cyclohexanone
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