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Compounds containing C, H, O atoms will have molecular weights that are even numbers. However, if one nitrogen is added the molecular weight will be an odd number. Test this by calculating the molecular weight of butanamide (CH3CH2CH2CONH2).
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a)
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85
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b)
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86
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c)
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87
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d)
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88
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| 2. |
Find the alkyl LOSS ion series in the spectra shown below. (Check the hint!)
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Click on image to enlarge
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a)
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29, 43, 57
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b)
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44, 58, 72
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c)
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none
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| 3. |
For this same spectrum, choose the compound that the spectrum represents.
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Click on image to enlarge
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a)
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propanamide
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b)
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acrylamide
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c)
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glycine
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d)
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thiocyanic acid, methyl ester
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e)
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N,N-dimethylformamide
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| 4. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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N,N-diethylacetamide
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b)
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N,N-diisopropylformamide
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c)
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pentanamide
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d)
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N-butylacetamide
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e)
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hexanamide
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| 5. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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2,2-dimethylpropanamide
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b)
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pentanamide
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c)
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N-(n-Propyl)ethanamide
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d)
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hexanamide
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e)
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N,N-dimethylacetamide
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| 6. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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butanamide
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b)
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2,2-dimethylpropanamide
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c)
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N,N-dimethylacetamide
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d)
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morpholine
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e)
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propanamide
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| 7. |
Choose the compound that this spectrum represents.
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Click on image to enlarge
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a)
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hydroxyacetonitrile
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b)
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urea
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c)
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isocyanatomethane
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d)
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methyl nitrite
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e)
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nitro methane
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